Apply Euler's method twice to approximate the solution to the initial value problem on the interval [0,21], first with step size h=0.25, then with step size h=0.1. Compare the three-decimal-place values of the two approximations at x=21 with the value of y(21) of the actual solution. y=3x2y,y(0)=6,y(x)=6ex3 The Euler approximation when h=0.25 of y(21) is (Type an integer or decimal rounded to three decimal places as needed.)