AR$20$

$$:

C$6$H$14($l$)=-198\mathrm{.}7$ kJ$/$mol C$3$H$8$O $($l$)=-302\mathrm{.}54$ kJ$/$mol

CO$2($g$)=-393\mathrm{.}5$ kJ$/$mol H$2$O $($g$)=-241\mathrm{.}82$ kJ$/$mol

$$:

C$-$C $=356$ kJ$/$mol C$-$H $=416$ kJ$/$mol

C$-$O $()=336$ kJ$/$mol C$=$O $()=803$ kJ$/$mol

O$=$O $=497$ kJ$/$mol O$-$H $=467$ kJ$/$mol

$1.$ n$-$Hexane $($C$6$H$14)-$

$)$ n$-$

b$)-$ a $$

$2.$

$)$

b$)$ a$)"$