Question: ((( Arduino C program ))) You are to build a simple system to convert Binary numbers read in on a bank of 4 switches (dip
((( Arduino C program )))
You are to build a simple system to convert Binary numbers read in on a bank of 4 switches (dip switch) to the corresponding Hex digit and display it on a 7-segment display.
You're to modify this program into a more compact version.
#include
#include
#define HEX_0 0x3F
#define HEX_1 0x06
#define HEX_2 0x5B
#define HEX_3 0x4F
#define HEX_4 0x66
#define HEX_5 0x6D
#define HEX_6 0xFD
#define HEX_7 0x07
#define HEX_8 0x7F
#define HEX_9 0x6F
#define HEX_A 0x77
#define HEX_B 0x7C
#define HEX_C 0x39
#define HEX_D 0x5E
#define HEX_E 0x79
#define HEX_F 0x71
uint8_t x;
int main(void)
{
//setup code goes here
DDRD = 0xFF;
DDRB = 0x00;
PORTB = 0xFF;
while (1)
{
x = PINB & 0x0F; //MASKING THE FIRST FOUR BITS OD PROTB TO 0 AND THE OTHER FOUR TO 1
if (x == 0)
{
PORTD = HEX_0;
}
else if (x == 1)
{
PORTD = HEX_1;
}
else if (x == 2)
{
PORTD = HEX_2;
}
else if (x == 3)
{
PORTD = HEX_3;
}
else if (x == 4)
{
PORTD = HEX_4;
}
else if (x == 5)
{
PORTD = HEX_5;
}
else if (x == 6)
{
PORTD = HEX_6;
}
else if (x == 7)
{
PORTD = HEX_7;
}
else if (x == 8)
{
PORTD = HEX_8;
}
else if (x == 9)
{
PORTD = HEX_9;
}
else if (x == 10)
{
PORTD = HEX_A;
}
else if (x == 11)
{
PORTD = HEX_B;
}
else if (x == 12)
{
PORTD = HEX_C;
}
else if (x == 13)
{
PORTD = HEX_D;
}
else if (x == 14)
{
PORTD = HEX_E;
}
else if (x == 15)
{
PORTD = HEX_F;
}
else
{
PORTD = HEX_0;
}
}
}
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
Study Help