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$\begin{array}{cc}?& \text{B}\text{o}\text{t}\text{t}\text{l}\text{e}\\ ?& ?\\ ?& \text{S}\text{a}\text{m}\text{p}\text{l}\text{e}\\ 1& 2\\ 3& 4\\ 1& 0\mathrm{.}582\\ 0\mathrm{.}582& 0\mathrm{.}582\\ 0\mathrm{.}607& 2\\ 0\mathrm{.}588& 0\mathrm{.}583\\ 0\mathrm{.}592& 0\mathrm{.}596\\ 3& 0\mathrm{.}579\\ 0\mathrm{.}618& 0\mathrm{.}610\\ 0\mathrm{.}576& 4\\ 0\mathrm{.}610& 0\mathrm{.}589\\ 0\mathrm{.}570& 0\mathrm{.}608\\ 5& 0\mathrm{.}578\\ 0\mathrm{.}620& 0\mathrm{.}578\\ 0\mathrm{.}575& 6\\ 0\mathrm{.}615& 0\mathrm{.}615\\ 0\mathrm{.}614& 0\mathrm{.}607\end{array}$

Click the icon $to$ view the table $of$ factors for calculating three$-$sigma $limits$ for the $\stackrel{}{x}-$chart and $R-$chart.

More Info

Assume that only these six samples are sufficient, and use the data $to$ determine control $limits$ for $anR-$ and $an\stackrel{}{x}-$chart.

Compute the range $R$ and the sample mean $\stackrel{}{x}for$ each sample. $(Enter$ your responses rounded $to$ three decimal places.$)$

$\begin{array}{cc}?& \text{B}\text{o}\text{t}\text{t}\text{l}\text{e}\\ ?& ?\\ ?& ?\\ ?& \text{S}\text{a}\text{m}\text{p}\text{l}\text{e}\\ 1& 2\\ 3& 4\\ R& \stackrel{}{x}\\ 1& 0\mathrm{.}582\\ 0\mathrm{.}582& 0\mathrm{.}582\\ 0\mathrm{.}607& 0\mathrm{.}025\\ 0\mathrm{.}588& 2\\ 0\mathrm{.}588& 0\mathrm{.}583\\ 0\mathrm{.}592& 0\mathrm{.}596\\ 0\mathrm{.}013& 0\mathrm{.}590\\ 3& 0\mathrm{.}579\\ 0\mathrm{.}618& 0\mathrm{.}610\\ 0\mathrm{.}576& 0\mathrm{.}042\\ 0\mathrm{.}596& 4\\ 0\mathrm{.}610& 0\mathrm{.}589\\ 0\mathrm{.}570& 0\mathrm{.}608\\ 0\mathrm{.}040& 0\mathrm{.}594\\ 5& 0\mathrm{.}578\\ 0\mathrm{.}620& 0\mathrm{.}578\\ 0\mathrm{.}575& 1\\ 1& 6\\ 0\mathrm{.}615& 0\mathrm{.}615\\ 0\mathrm{.}614& 0\mathrm{.}607\\ 1& 1\end{array}$

The $UC{L}_R$ equals inches and the $LC{L}_{R}LC{L}_{R}is$ negative, enter this value $as0.UC{L}_{\stackrel{}{x}}$ equals inches and the $LC{L}_{\stackrel{}{x}}$ equals inches. $(Enter$ your responses rounded $to$ three decimal places.$)$