Arsenious acid,H3As03 ionizes to the equationH3Aso3(aq)=H+(aq)+H2Aso3-(aq) The value of the ionization ofconstant for this equilibrium 6.0E-10 at
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Arsenious acid,H3As03 ionizes to the equationH3Aso3(aq)=H+(aq)+H2Aso3-(aq) The value of the ionization ofconstant for this equilibrium 6.0E-10 at 25C. For a 0.60 M solutionof H3AsO3, calculate the ph and the percent ionization.
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