Question: As I made a CV(E-i) graph on a cell with a working electrode (Pt, Au, GC) potential vs. Ag/AgCl and electrolyte containing FcMeOH and NaClO4

As I made a CV(E-i) graph on a cell with a working electrode (Pt, Au, GC) potential vs. Ag/AgCl and electrolyte containing FcMeOH and NaClO4

1. why there are no difference of formal potential btw three working electrodes?

2. why we scan the potential -1.0V to 6.0V?

Step by Step Solution

There are 3 Steps involved in it

1 Expert Approved Answer
Step: 1 Unlock blur-text-image
Question Has Been Solved by an Expert!

Get step-by-step solutions from verified subject matter experts

Step: 2 Unlock
Step: 3 Unlock

Students Have Also Explored These Related Chemical Engineering Questions!