Question: As I made a CV(E-i) graph on a cell with a working electrode (Pt, Au, GC) potential vs. Ag/AgCl and electrolyte containing FcMeOH and NaClO4
As I made a CV(E-i) graph on a cell with a working electrode (Pt, Au, GC) potential vs. Ag/AgCl and electrolyte containing FcMeOH and NaClO4
1. why there are no difference of formal potential btw three working electrodes?
2. why we scan the potential -1.0V to 6.0V?
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