As stated in the previous problem, in a small town, 50% of single family homes have a front porch. 48 single family houses are randomly selected. If X represents the number of single family homes with a porch, then the distribution of X can be approximated with a normal distribution, N(24, 3.5), where the mean () is 24 and standard deviation (o) is 3.5. Using this approximation, find the probability that 27 or 28 single family homes will have a porch. You may use the portion of the Standard Normal Table below. Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.6 0.7257 0.7291 0.7324 0.7357 0.7389 0.7422 0.7454 0.7486 0.7517 0.7549 0.7 0.7580 0.7611 0.7642 0.7673 0.7704 0.7734 0.7764 0.7794 0.7823 0.7852 0.8 0.7881 0.7910 0.7939 0.7967 0.7995 0.8023 0.8051 0.8078 0.8106 0.8133 0.9 0.8159 0.8186 0.8212 0.8238 0.8264 0.8289 0.8315 0.8340 0.8365 0.8389 1.0 0.8413 0.8438 0.8461 0.8485 0.8508 0.8531 0.8554 0.8577 0.8599 0.8621 1.1 0.8643 0.8665 0.8686 0.8708 0.8729 0.8749 0.8770 0.8790 0.8810 0.8830 1.2 0.8849 0.8869 0.8888 0.8907 0.8925 0.8944 0.8962 0.8980 0.8997 0.9015 1.3 0.9032 0.9049 0.9066 0.9082 0.9099 1.4 0.9192 0.9207 0.9222 0.9236 0.9251 0.9115 0.9131 0.9147 0.9162 0.9177 0.9265 0.9279 0.9292 0.9306 0.9319 Round the final answer to two decimal places.