As we saw in Example $3\mathrm{.}5,$ the presst same as if the fluid were static. From $t$ that $p_3=h_{4-3}.$ Thus, since $h_{3-1}+h_4$

By combining these two equations we see that

$p_3-p_4=\frac{1}{2}{V}^2$

which can be rearranged to give

$**,V=\sqrt[\phantom{2}]{2\frac{p_3-p_4}{}}$

$p_{}=h$

The actual shape and size of Pitot$-$static tubes vary considerably. Some of the more common types are shown in Fig. $3\mathrm{.}7.$

$\frac{p_3}{}=h_3$

:$.p_3=h_3$

$20+0\frac{\text{e}\text{x}\text{a}\text{t}\text{i}}{x+0^2}$