As you remember from the Circuit Theory 1 course, the current equation for capacitance is Laplace transform formula (1), when C 1.091e-6 F, uc(t tand the initial state of the capacitance voltage is 4 V Ic(s The circuit in Figure 1 is related to tasks B) and C). d ic(t) = C. c(t) (1). B) [max. 15%] Write the equation of the loop current il of the circuit in Fig. 1 in Laplace transform (loop current method). Tips and instructions: Write the equation so that there is zero to the right of the equal sign The following variables must be included in the equation: [11, R1,IL, R2, L1,10,s] 10 describes the initial state of the inductance current Laplace-transformed currentIL ( s is described by the variable IL. Laplace-transformed currentI(s is described by the variable 11. 11 Figure 1 R1 R2 uL L1 iL C) [max. 20%] In the circuit of Figure 1 R1 = 1000 Ohms R2 = 11000 Ohms L1 = 12.0H 11(t) = 1/200 A (whose Laplace transform is (1/200)) 10 = 1/2750A Solve for the Laplace-transformed response IL: IL (8 Hint: Put the numerical values into the equation in B and solve for IL ieIL ( s .) Solve the inverse Laplace transform iL of the previous answer: iL ( t)