ASN4: Problem 6 (1 point) Electrostatic fields in charged regions: In a p-n junction there is a so-called space-charge region (not positive charge on the electron donorin-dope side of the junction, negative on acceptorip side). The sum of charges in the two sections is zero. This charged region creates band bending. In this question we show that for regions of constant charge density this band bending is parabolic in form. Follow the steps below: Part d) Now instead the charge is spread through a thickness 41- Use Gauss's Law to show that the field rises or falls linearly within each region of constant charge, where each section has a charge per volume of p and -p. See the diagram. Assume a = 0 is the left edge. Enter as a function of W. I, e; p, c (enter as tho, epsilon) aw - p *=0 x=W First find E on the positive side as a function of these variables: E4 = On the negative side: 2 - -rho/epsilon(x-2W) #: Part e) Use your result to find the energy of the conduction band edge I'm in each region relative to the conduction band Ep as a function of * using the previously given variables In positive region: (Enter ONLY the term with the highest power of x) UC - Ec= In negative region: (Enter ONLY the term with the highest power of x ) Vo - Ec= Part () Find built in potential ev, as a function of the above variables e Var=