Assign point dist with the distance between point $(x1,y1)$ and point $(x2,y2).$ The calculation is:

Distance $=\sqrt[\phantom{2}]{(x2-x1{)}^2+(y2-y1{)}^2}$

Sample output with inputs: $1\mathrm{.}02\mathrm{.}01\mathrm{.}05\mathrm{.}0$

Points distance: $3\mathrm{.}0$

Note: For nested function calls, ensure each function has an opening and closing parenthesis. Otherwise, a SyntaxError will be raised pointing to the next line of code.

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$528580\mathrm{.}2119266.x3z$ qqy $7$

import math

x$1=$ float $($input$())$

y$1=$ float$($input$())$

$x_2=$ float$($input$())$

$y^2=$ float $($input $())$

$7$

$8\text{'}"\text{'}$ Your solution goes here $\text{'}"\text{'}$

$9$

$10$ print$($f$\text{'}$Points distance: $\{$point$\_$dist:. $1$f $\}\text{'})$