Question: Assume a computer is using 3 2 bit virtual addresses and two - level paging. Address division scheme is: ( 1 0 , 1 0

Assume a computer is using 32 bit virtual addresses and two-level paging. Address division scheme is: (10,10,12). That means offset is 12 bits long. What is the page size? Find out the amount of physical memory (in KB) required for the page table information of a program with the following address space layout. The gray areas are used VM regions.

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