Question: Assume that a randomly selected subject is given a bone density test. Those tests follow a standard normal distribution. Find the probability that the bone

Assume that a randomly selected subject is given a bone density test. Those tests follow a standard normal distribution. Find the probability that the bone density score for this subject is between -1.03 and 2.01.

How would I explain this in words with the answer

so far I got With this test being the standard normal distribution of bone density the scores will have the calculation 0 for the mean and 1 for the standard deviation.

P(-1.03 < z <2.01) = P(z <2.01)-P(z < -1.03 )

To getP(z <2.01)use excel function =NORM.S.DIST(2.01,TRUE)

To getP(z <-1.03)use excel function =NORM.S.DIST(-1.03,TRUE)

The answer to this probability is 0.826279 from the reason that we are needing to find the probability that the bone density score for this subject is between -1.03 and 2.01.

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