Question: Assume that f(x) is a one-to-one, differentiable function with values given on the following table.table[[x,0,1,2,4],[f(z),2,1,4,0],[f'(z),-1,-8,-7,-5]]Find the following values.(a)f-1(0)=(b)(f-1)'(0)=

Assume that f(x) is a one-to-one, differentiable function with values given on the following table.\table[[x,0,1,2,4],[f(z),2,1,4,0],[f'(z),-1,-8,-7,-5]]Find the following values.(a)f-1(0)=(b)(f-1)'(0)=

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