Question: Assume that m = 0 . 0 0 0 2 errors per hour, n = 0 . 0 0 5 failures per hour, m =

Assume that m=0.0002 errors per hour, n=0.005 failures per hour, m=0.05 repairs per hour, and n=0.06 repairs per hour. Calculate:
a) The steady-state probability of system failure due to maintenance error?
b) The system steady-state availability?
The system can fail due to preventive maintenance-related human error and nonhuman error. The values of human and nonhuman error rates are 0.0006 errors per hour and 0.007 failures per hour, respectively. Calculate the probability of (1) the system normally? And (2) failure due to maintenance error? And (3) non-maintenance error? for a 200-h mission?
Assume that m=n=0. Develop an expression for the system mean time to failure
Assume that m = 0 . 0 0 0 2 errors per hour, n =

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