Question: Assume that the differential equation for the function y ( t ) , y a 1 y a 0 y = 0 , has a

Assume that the differential equation for the function y(t),y a1y a0y=0,has a characteristic polynomial with a repeated root, r0.What are fundamental solutions of the differential equation above?A. y1(t)=er0t,y2=er0tB. y1(t)=2er0t,y2=7ter0tC. There is only one fundamental solution: y1(t)=er0tD. There are no fundamental solutions.E. y1(t)=er0t,y2=er0tF. y1(t)=er0t,y2=ter0tG. y1(t)=ter0ty2(t)=er0tH. y1(t)=er0t,y2=2er0tI. None of the AboveNote: Select all the correct answers.

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