Assume that there is no syntax error. Points: 1 x 3 = 3 a) int i-5, 3--2, 6-0, W,x,y,z; w=i11 311 ki inti-1.j=5; x = i 66 ) && !k; if (11 y-ill) 66 k; printf("%d... %d", i+1, j+1); Z - I66) Ilk; printf("%d... %d", i, j); printf(" -id xuld yotd z-1d", w, x, y, z) Output: Output: Output: c) int x = 50; int change( int i) i + 5; x=100; int c - 580; return c 2. Find out and correct the errors in the foll program segment so that the message is display the appropriate case. (Writing the solution wi && ll operator will get full credit. Using & get 50%) Point:1 int main() int i = 45, C; x - 2e; printf("%d",i+2): C- change ( 1); printf(" d %d %d", i, c, x); return ; void main() int a, b: scanf("did", a, b); if (a