Assume that

$v=\frac{dE}{dL}\frac{}{4}(r_0^2-r^2)$

show that for laminar flow using average velocity $($HINT$!v_{\text{m}\text{a}\text{x}}=2V$ at the $r=0).$

Describe in detail why the maxmimum velocitiy $(v_{\text{m}\text{a}\text{x}})$ is twice the average velocity $(V)$

$\frac{dE}{dL}=\frac{32V}{d^2}$