Assume you have a byte$-$addressable machine that uses $32-$bit integers and you are storing

the hex value $3456$ at address $0.$

a$)$ Show how this is stored on a big endian machine.

b$)$ Show how this is stored on a little endian machine.

c$)$ Assume you store $(3456){?}_{16}$ using $16$ bits at address $0.$

If you wanted to increase the hex value to $(123456{)}_{16},$ which byte assignment

would be more efficient: big or little endian? Explain your answer.