Question: Assume you have compiled a C++ program with a main(int argc, char* argv[]) function down to the executable a.out. If you execute. /a.out from the

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Assume you have compiled a C++ program with a main(int argc, char* argv[]) function down to the executable a.out. If you execute. /a.out from the command line, what will be stored in argc? (nothing) ./a.out Given the following program code: 1 #include
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