Assuming in each case that T$($n$)$ is eventually nondecreasing, use Theorem

B$.6$ to determine the order of the following recurrence equations:

$($a$)$ T$($n$)=14$T$(($n$)/(5))+6$n$,$ for n$>25,$n a power of $5$

T$(25)=60$

$($b$)$ T$($n$)=4$T$(($n$)/(4))+2$n$^(2),$ for n$>16,$n a power of $4$

T$(16)=50$