Question: Assuming ptr is a pointer variable, what will the following statement output? cout * ptr; The value stored in the variable whose address is contained

Assuming ptr is a pointer variable, what will the following statement output? cout *ptr;
The value stored in the variable whose address is contained in ptr.
The string ?**** ptr":
The address of the variable stored in ptr.
The address of the variable whose address is stored in ptr.
None of these
Assuming ptr is a pointer variable, what will the following statement

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