Question: Assuming that the following function is defined properly: def pass_it(x, y, e, s): print(x, y, end=e, sep=s) What will be the result of the following

 Assuming that the following function is defined properly: def pass_it(x, y,

Assuming that the following function is defined properly: def pass_it(x, y, e, s): print(x, y, end=e, sep=s) What will be the result of the following function call if num1 is set to 5 and num2 set to 3? pass_it (numl, num2, " ","") PS: In case you don't see the picture of the function, here is the link: https://pasteboard.co/JBlb54o.png Your answer: 5* o 3* o 53 0 5*3 0 53* Assuming that the following function is defined properly: def pass_it(x, y, e, s): print(x, y, end=e, sep=s) What will be the result of the following function call if num1 is set to 5 and num2 set to 3? pass_it (numl, num2, " ","") PS: In case you don't see the picture of the function, here is the link: https://pasteboard.co/JBlb54o.png Your answer: 5* o 3* o 53 0 5*3 0 53*

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