At a given instant, a particle with mass $5\mathrm{.}00103$kg and charge $3\mathrm{.}50108$C has velocity of magnitude of $2\mathrm{.}00105$m$/$s in the $+$y direction. It is moving in a uniform magnetic field of magnitude $0\mathrm{.}8$T directed $40$ degrees clockwise from the $$x direction. Use the right$-$hand rule to determine which of the following gives the direction of the magnetic force on the charge. A$)$ to the left B$)$ to the right C$)$ upward D$)$ downward E$)$ out of the screen F$)$ into the screen