Question: At a time t = 2 . 8 0 s , a point on the rim of a wheel with a radius of 0 .

At a time t=2.80s, a point on the rim of a wheel with a radius of 0.190m has a tangential speed of 54.0ms as the wheel slows down with a tangential acceleration of constant magnitude 10.9ms2.
Part A
Calculate the wheel's constant angular acceleration.
Express your answer in radians per second squared.
=
rads2
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Part B
Calculate the angular velocity at t=2.80s.
Express your answer in radians per second.
=
rads
Part C
Calculate the angular velocity at t=0.
Express your answer in radians per second.
0=
rads
Part D
Through what angle did the wheel turn between t=0 and t=2.80s?
Express your answer in radians.
=
rad
Part E
Prior to the wheel coming to rest, at what time will the radial acceleration at a point on the rim equal g=9.81ms2?
Express your answer in seconds.
t=
S
 At a time t=2.80s, a point on the rim of a

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