At $\backslash ($ t$=0\backslash ),$ the instantaneous position of two pulses moving along a taut string with a speed $\backslash ($ v$=2\mathrm{.}42\backslash$mathrm$\{$~cm$\}/\backslash$mathrm$\{$s$\}\backslash )$ are as shown in the diagram below. Each unit on the horizontal axis is $2\mathrm{.}0$ cm and each unit on the vertical axis is $6\mathrm{.}0$ cm $.$

$($a$)$ At what location will the resultant of the two pulses have minimum amplitude?

The amplitude of the resultant will be minimum when the two peaks overlap. How far does each pulse move to get to this position? cm

$($b$)$ At what time will the resultant of the two pulses have minimum amplitude?

What is the relationship between speed, time, and distance? s

$($c$)$ What is the value of this minimum amplitude?

What is the height of each pulse, given that each unit on the vertical axis is $6\mathrm{.}0$ cm $?$ cm