Question: At t1 = 2.0 s an object's velocity is v1 = 4.540 m/s to the EAST, and at t2 = 12.0 s its velocity is

At t1 = 2.0 s an object's velocity is v1 = 4.540 m/s to the EAST, and at t2 = 12.0 s its velocity is v2 = 19.340 m/s to the WEST. Assuming a constant acceleration, Take EAST as the positive direction. What is its acceleration with a proper sign? Keep 3 digits after the decimal point

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