At the highest point, the damage $($and the capillary front$)$ reaches$1\mathrm{.}2$m above the room floor. An inspector detected that the capillary water is drawn from ground water in contact with foundation of the building. The free surface of that water is some $2\mathrm{.}0$m below the floor of the room. Jill is waiting for a belated repair crew $($Acme Ltd$.)$ and killing the time with trivial calculations.

She knows the density of water! She checks her yellowed lecture notes to find the surface tension of free water surface at $20($no WiFi connection$)$ and uses an old volume of Encyclopedia Britannica left behind by the former owner, to find out that the contact angle between water and the cement paste likely used both as mortar and in the foundation wall and as binder of the stucco $($an interconnected porous structure$)$ is $15$

That is all she needs to calculate the average radius of the small pores in the cement paste.

Oh$,$ almost... but then it is hard not to remember that the gravitational acceleration at the surface of our planet is g$=9\mathrm{.}81$m$/$g$^2$

Sadly, Jill's notes with these calculations have not been preserved.

Instruction:

Recreate Jill's calculations based on data provided in the prompt.

Hint: start with a survey of quantities, values and units.