Question: At the lower limit, use the standard limit lim 0 + sin = 1 lim R0 + R sinR =1: ( sin ) 0 +

At the lower limit, use the standard limit lim 0 + sin = 1 lim R0 + R sinR =1: ( sin ) 0 + + 1. ( R sinR ) R0 + +1. why is it = 1

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