Question: At time t = 0 , a 3 . 0 kg particle with veloc - ity v = ( 5 . 0 m / s

At time t =0, a 3.0 kg particle with veloc-
ity v
=(5.0 m/s)i
(6.0 m/s)j
is at x =3.0 m, y=8.0 m. It is pulled
by a 7.0 N force in the negative x direction. About the origin, what
are (a) the particles angular momentum, (b) the torque acting on the
particle, and (c) the rate at which the angular momentum is changing?

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