Question: At time t = 1 8 s , the velocity of a particle moving in the x - y plane is v = 0 .

At time t=18s, the velocity of a particle moving in the x-y plane is v=0.05i+2.56jms. By time t=18.09s, its velocity has become
-0.10i+2.42jms. Determine the magnitude aav of its average acceleration during this interval and the angle made by the average
acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis.
Answers:
At time t=18s, the velocity of a particle moving in the

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