At time t, 7') = 9.6Ot2 i - (9.90t + 1.00t2) ?gives the position of a 3.0 kg particle relative to the origin of an xy coordinate system ( 7') is in meters and t is in seconds). (a) Find the torque acting on the particle relative to the origin at the moment 2.01 s (b) Is the magnitude of the particle's angular momentum relative to the origin increasing, decreasing, or unchanging? la) n? n E Units N-m v eTextbook and Media Assistance Used Hint Assistance Used Velocity is the time derivative of the position vector. (You must retain the vector notation.) Momentum is the product of mass and velocity. Angular momentum is the cross product of the position vector and the momentum vector. Torque is the time derivative of the angular momentum. Key Ideas - Newton's second law for a particle can be written in angular form as where am is the net torque acting on the particle and 7 is the angular momentum of the particle