Question: Attempt 1 : 2 0 attempts remaining. The differential equation x 2 d 2 y d x 2 - 7 x d y d x

Attempt 1:20 attempts remaining.
The differential equation
x2d2ydx2-7xdydx16y=0
has x4 as a solution.
Applying reduction order we set y2=ux4.
Then (using the prime notation for the derivatives)
y2'=
y2''=
So, plugging y2 into the left side of the differential equation, and reducing, we get
x2y2''-7xy2'16y2=
Attempt 1 : 2 0 attempts remaining. The

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