Attempt $1$: $4$ attempts remaining.

Let $f(x)=sin(arccos(x)).$

$a.$ First, determine the derivative $by$ using Chain Rule.

$f^{\text{'}}(x)=\frac{-cos(arccos(x))}{\sqrt[\phantom{2}]{1-x^2}}$

$b.$ Next, determine the derivative $in$ a different way.

Rewrite $f(x)x.$

$f(x)=$

$c.$ Then find the derivative $of$ this equivalent form $off.$

$f^{\text{'}}(x)=$