Question: Attempt 4 : 1 7 attempts remaining. Solve the initial value problem: y ' ( x ) = - 4 y ( x ) +

Attempt 4: 17 attempts remaining.
Solve the initial value problem:
y'(x)=-4y(x)+442,y(0)=7
y(x)=
Note: observe that the y(x) under the square root is not y times x. It is function notation, i.e."y of x".
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Attempt 4 : 1 7 attempts remaining. Solve the

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