attempts left Check my work Enter your answer in the provided box. A technique called photoelectron spectroscopy is used to measure the ionization energy of atoms. A sample is irradiated with UV light, and electrons are ejected from the valence shell. The kinetic energies of the ejected electrons are measured. Because the energy of the UV photon and the kinetic energy of the ejected electron are known, we can write hv-IE+ 1 2 my where v is the frequency of the UV light, m and a are the mass and velocity of the electron, respectively, and his Planck's constant. In one experiment, the kinetic energy of the ejected electron from potassium is found to be 5.34 x 10-19 J using a UV source of wavelength 162 nm. Calculate the lonization energy of potassium. 6.92 mol 10 Next > # Hint Solution Guided Solution ING 126 AM