Question: Average arrival rate, 1 = 20 per 8 hour = 2.5 per hour Average service rate, u = 1 in 40 minutes = 15 per

Average arrival rate, 1 = 20 per 8 hour = 2.5 per hour Average service rate, u = 1 in 40 minutes = 15 per hour Number of servers, s = 3 (a) Fraction of time each server is busy = 1/ s.p = 2.5/(3*1.5) = 0.56 (b) Use the following two formulae to find the idle server probability (Po) and average waiting time (Wa). 1 fors > 1.41 0 n! - . AM P (3-1)(1.4-2 Using 1 = 2.5, y = 1.5, and s= 3, we get, Po = 0.173 and Wa = 0.15 hours or 9 minutes (c) The average number of callers waiting, Lg=W9* = 0.15*2.5 = 0.375 (d) The average time a caller in on phone (waiting + calling). Ws = Wq+average service time = 9+40 = 49 minutes (e) The average no. of callers with phone, Ls = W; 1= (49/60)*2.5 = 2.04 (f) Idle server probability (PO) has been already computed in part-b which os Po = 0.173 Average arrival rate, 1 = 20 per 8 hour = 2.5 per hour Average service rate, u = 1 in 40 minutes = 15 per hour Number of servers, s = 3 (a) Fraction of time each server is busy = 1/ s.p = 2.5/(3*1.5) = 0.56 (b) Use the following two formulae to find the idle server probability (Po) and average waiting time (Wa). 1 fors > 1.41 0 n! - . AM P (3-1)(1.4-2 Using 1 = 2.5, y = 1.5, and s= 3, we get, Po = 0.173 and Wa = 0.15 hours or 9 minutes (c) The average number of callers waiting, Lg=W9* = 0.15*2.5 = 0.375 (d) The average time a caller in on phone (waiting + calling). Ws = Wq+average service time = 9+40 = 49 minutes (e) The average no. of callers with phone, Ls = W; 1= (49/60)*2.5 = 2.04 (f) Idle server probability (PO) has been already computed in part-b which os Po = 0.173

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