AZn wire and $A\frac{g}{A}gCl$ reference electrode saturated with $)=(0\mathrm{.}197V$ are placed into a solution of $ZnS{O}_4.$ The $Zn$ wire is attached to the positive terminal and the $A\frac{g}{A}gCl$ electrode is attached to the negative terminal of the potentiometer. Calculate the $Z{n}^{2+}$ in the solution if the cell potential, $E_{\text{c}\text{e}\text{l}\text{l}},$ is $-1\mathrm{.}060V.$ The standard reduction potential of the $Z{n}^2\frac{+}{Z}n$ half$-$reaction is $-0\mathrm{.}762V.$

$[Z{n}^2]=$

Incorrect