$\frac{?}{\text{b}\text{a}\text{r}}(v{)}^3\frac{-}{b}ar(v{)}^2(b+\frac{RT}{p})+\frac{a}{p}\frac{?}{\text{b}\text{a}\text{r}}(v)-\frac{ab}{p}=0$

$((\frac{?}{\text{b}\text{a}\text{r}}(v))\frac{-}{b}ar(v{)}^{\text{'}})*((\frac{?}{\text{b}\text{a}\text{r}}(v))\frac{-}{b}ar(v{)}^{\text{'}\text{'}})*((\frac{?}{\text{b}\text{a}\text{r}}(v))\frac{-}{b}ar(v{)}^{\text{'}\text{'}\text{'}})=0$

The cubic equation

$((\frac{?}{\text{b}\text{a}\text{r}}(v))\frac{-}{b}ar(v{)}^{\text{'}})*((\frac{?}{\text{b}\text{a}\text{r}}(v))\frac{-}{b}ar(v{)}^{\text{'}\text{'}})*((\frac{?}{\text{b}\text{a}\text{r}}(v))\frac{-}{b}ar(v{)}^{\text{'}\text{'}\text{'}})=0$

canbe written

$?$ Con you please explain in detail how we transformed this equation into that form?