$($b$)$ After the car is driven, the temperature and volume of air in the tire have changed. Let Td be the temperature and Vd be the volume of air in the tire. We have

PdVdPfVf

$=$

TdTf

$,$

which gives

Pd$=$Pf$$

VfVd

TdTf

$=$

$105$ Pa

$$

Vf$$

K

Vf$$

K

$=105$ Pa$.$

Again we see that the volume Vf cancels out of the equation.