(b) (i) (ii) (iii) (iv) (3+c)u +(4+uu tru =0 (2+x)ux +(5+ y)uy + 3xu = 0...

Transcribed Image Text:

(b) (i) (ii) (iii) (iv) (3+c)u +(4+uu tru =0 (2+x)ux +(5+ y)uy + 3xu = 0 (6+x)ux +(2+ y)uy + (5 + x)u = 0 (5+x)ux +(4+ y)uy + (x+3)u = 0 (c) (i) (ii) (iii) (iv) (3+x)+(4+y) uy = = 2u +4 (2+x)ux + (5+ y)uy = 5u +3 (6+x)ux +(2+ y)uy = 6u + 1 (5+x)ux +(4+ y)uy = 7u + 2 Separable PDES Q1.Reduce the following PDE equation to ODEs via separable method only (No need to Integrate them) in terms of y=y(x), u=u(x) and u=u(y) (a) (i) (ii) (iii) (iv) 3ux + 4y +2u = 0 2ux + 5uy5u = 0 3ux+2uy +6u = 0 5ux + 4uy - 2u = 0 (b) (i) (ii) (iii) (iv) (3+c)u +(4+uu tru =0 (2+x)ux +(5+ y)uy + 3xu = 0 (6+x)ux +(2+ y)uy + (5 + x)u = 0 (5+x)ux +(4+ y)uy + (x+3)u = 0 (c) (i) (ii) (iii) (iv) (3+x)+(4+y) uy = = 2u +4 (2+x)ux + (5+ y)uy = 5u +3 (6+x)ux +(2+ y)uy = 6u + 1 (5+x)ux +(4+ y)uy = 7u + 2 Separable PDES Q1.Reduce the following PDE equation to ODEs via separable method only (No need to Integrate them) in terms of y=y(x), u=u(x) and u=u(y) (a) (i) (ii) (iii) (iv) 3ux + 4y +2u = 0 2ux + 5uy5u = 0 3ux+2uy +6u = 0 5ux + 4uy - 2u = 0

Answer rating: 100% (QA)

To classify the given secondorder partial differential equations we need to analyze their characteri... View the full answer