$($b$)$ Natural ventilation can improve indoor environmental quality. A building is

located in a large suburban area, where the wind exponent is $0\mathrm{.}33,$ and the

boundary layer height of the wind is $460m.$ The design wind velocity from

measurements at a nearby station is $10\frac{m}{s}$ at a measurement height of $10m,$ where

the boundary layer height for the station is $270m$ and the wind exponent for the

station is $0\mathrm{.}14.$ The wind $($pressure$)$ coefficient of the windward wall $b$ is $0\mathrm{.}8,$ the

wind $($pressure$)$ coefficient of the leeward wall is $-0\mathrm{.}2,$ and the flow coefficient

of openings is $0\mathrm{.}65.$ The window opening sizes on the two opposite walls are $6m^2$

and $10m^2$ respectively, and air density is $1\mathrm{.}2k\frac{g}{m^3}.$ With the following given

equations, determine

$($i$)$ the wind pressure at openings of the building walls,

$($ii$)$ the effective flow area in the flow path from one side to the opposite side of

the building, and

$($iii$)$ the flow rate of the building due to the wind.

$(10$ marks$)$

Note: Equations are given as follows $($with Abbreviations and symbols being

appeared as their usual meaning$)$:

$C_h=(\frac{{}_{\text{m}\text{e}\text{t}}}{H_{\text{m}\text{e}\text{t}}}{)}^{2a_{\text{m}\text{e}\text{t}}}(\frac{H}{}{)}^{2a}$

$p_w=\frac{1}{2}(\frac{?}{\text{b}\text{a}\text{r}}(C{)}_{w1}\frac{-}{b}ar(C{)}_{w2})K_w{}_o{U}_H^2$

$A_e=(\frac{1}{A_1^2}+\frac{1}{A_2^2}+\frac{1}{A_3^2}{)}^{-\frac{1}{2}}$

$V_T^{}=K_{0}C{A}_e\sqrt[\phantom{2}]{\frac{2p}{}}$