B. Refer to Figure 15. Use the same conditions provided in Section 1.6.1 to answer the followings a) Write down the mass balance equation and compute the steady-state CO concentrations b) Calculate the residence time, t. of CO. c) If the card party and smoking start at 10pm, what is the CO concentration at 10:307 Re. make Figure 1.6 using Excel spreadsheet and show the results. O Camb Infiltrated Air Cumb Intake Fan Application of CSTR Example (Figure 1.5) Outdoor Concentration. Camb Indoor Concentration, Room Volume, V Source Rate, s Airflow Rates. O First-order removal. Exhaust Fan Exfiltrated Air 0.0 VOC = . Application of CSTR Example (Figure 1.5) Now consider how quickly CO concentration buildup. V = 80 m, Qin = Qout = 40 m3/h Four card players have been smoking for several hours, each at a rate of four cigarettes per hour and each cigarette produces 125 mg of CO. S = 4 x 4 *125 mg/hour CO decays with a rate constant k = 0.1 h! Assuming the ambient concentration of CO is negligible (Camb=0), steady-state concentration of CO in the room is Qun Camb +5 2000 mg/hour Css = 41.7mg/m kV + Qout 0+30m + 40 Q: If the card party and smoking start at 10 pm, what is the CO concentration at 10:30 pm? Qout . M A:C(t) = Css{1 exp[- Cous + k)t}} B. Refer to Figure 15. Use the same conditions provided in Section 1.6.1 to answer the followings a) Write down the mass balance equation and compute the steady-state CO concentrations b) Calculate the residence time, t. of CO. c) If the card party and smoking start at 10pm, what is the CO concentration at 10:307 Re. make Figure 1.6 using Excel spreadsheet and show the results. O Camb Infiltrated Air Cumb Intake Fan Application of CSTR Example (Figure 1.5) Outdoor Concentration. Camb Indoor Concentration, Room Volume, V Source Rate, s Airflow Rates. O First-order removal. Exhaust Fan Exfiltrated Air 0.0 VOC = . Application of CSTR Example (Figure 1.5) Now consider how quickly CO concentration buildup. V = 80 m, Qin = Qout = 40 m3/h Four card players have been smoking for several hours, each at a rate of four cigarettes per hour and each cigarette produces 125 mg of CO. S = 4 x 4 *125 mg/hour CO decays with a rate constant k = 0.1 h! Assuming the ambient concentration of CO is negligible (Camb=0), steady-state concentration of CO in the room is Qun Camb +5 2000 mg/hour Css = 41.7mg/m kV + Qout 0+30m + 40 Q: If the card party and smoking start at 10 pm, what is the CO concentration at 10:30 pm? Qout . M A:C(t) = Css{1 exp[- Cous + k)t}}