Question: (b) Since 61 is a prime with 61 = 1 (mod 12) the polynomial X2 + 3 has roots in Z/61Z by (a): they

(b) Since 61 is a prime with 61 = 1 (mod 12)

(b) Since 61 is a prime with 61 = 1 (mod 12) the polynomial X2 + 3 has roots in Z/61Z by (a): they are 27 +61Z (you do not need to verify this). Using this information, give the roots of the polynomial X2 - X+19 in Z/61Z.

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11 Given roots of the polynomial X3 are 2761Z square root of 3 in 7612 27612 That is No... View full answer

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