$($b$)$ Use the force influence table in part $($a$)$ to draw the influence line for member $(4).\backslash$table$[[$MEMBER$,$P$\_(2)=1$kip,P$\_(3)=1$kip,P$\_(4)=1$kip$],[(1),-1\mathrm{.}68,-1\mathrm{.}12,-0\mathrm{.}55],[(2),-0\mathrm{.}55,-1\mathrm{.}12,-0\mathrm{.}55],[(3),-0\mathrm{.}55,-1\mathrm{.}12,-0\mathrm{.}55],[(4),-0\mathrm{.}55,-1\mathrm{.}12,-1\mathrm{.}6$g$],[(5),0\mathrm{.}5,1,1\mathrm{.}5],[(6),0\mathrm{.}5,1,1\mathrm{.}5],[(7),1\mathrm{.}5,1,0\mathrm{.}5],[(8),1\mathrm{.}5,1,0\mathrm{.}5],[(9),0,0,0],[(10),0\mathrm{.}5,0,0\mathrm{.}5],[(11),0,0,0],[(12),-1\mathrm{.}12,0,0],[(13),0\mathrm{.}25,0\mathrm{.}5,0\mathrm{.}75],[$R$\_(1),0\mathrm{.}75,0\mathrm{.}5,0\mathrm{.}25]]($c$)$ Determine the following for $P_1=P_5=6$ kip, $P_3=10$ kip and $P_2=P_4=12$kip

$($i$)$ The force for member $(4).$

$F_{(4)}=$

$($ii$)$ The vertical displacement at joint $7.$

$v=$

$($iii$)$ The horizontal displacement at joint $5.$

$u=$

$($iv$)$ The vertical reaction at joint $1.$

$R_1=$