$($b$)$ Using partial fractions, you could find that

$\frac{-2x^{2}x12}{(x-2{)}^2(x1)}=\frac{2}{(x-2{)}^2}-\frac{3}{x-2}\frac{1}{x1}$

Use this to find

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{-2x^{2}x12}{(x-2{)}^2(x1)}dx$