$($b$)$ What will be the yield strength$-$ductility combination of an oil$-$quenched $4340$ steel specimen that is subjected to this same tempering treatment?

$($b$)$ yield strength $=$

MPa

ductility $=$

$\backslash \%$RA

$($Note: To solve this problem, you will need to consult at least one of the figures below.$)$

Figure $11.$R$4$ For a water$-$quenched $\backslash (0\mathrm{.}40\backslash$mathrm$\{$wt$\}\backslash \%\backslash$mathrm$\{$C$\}\backslash )$ iron$-$carbon alloy $($a$)$ room temperature tensile and yield strength versus tempering temperature; $($b$)$ room temperature ductility $(\backslash \%$EL and $\backslash \%$RA$)$ versus tempering temperature.

Figure $11.$R$5$ For a oil$-$quenched alloy steel $($type $4340)($a$)$ room temperature tensile and yield strength versus tempering temperature; $($b$)$ room temperature ductility $(\backslash \%$EL and $\backslash \%$RA$)$ versus tempering temperature.