B=4

C programming

1 - void print(int a[],int b){

for(int i=0;i

printf("%d ",a[i]);

}

printf(" b=%d ",b);

}

2 - void function1(int a[],int b){

a[b]=a[b]+b;

b=b+2;

}

void function2(int a[],int *b){

a[*b]=a[*b]-*b;

*b=a[*b];

}

3 - void print(int a[],int b){

for(int i=0;i

printf("%d ",a[i]);

}

printf(" b=%d ",b);

}

void function1(int a[],int b){

a[b]=a[b]+b;

b=b+2;

}

void function2(int a[],int *b){

a[*b]=a[*b]-*b;

*b=a[*b];

}

2) Let array a be (5,4,9,8,7,3,1,2,0.6) and b be the last digit of your student number. Accordingly, if we run the given functions in the following order, what will be the output? Explain step by step. function(a,b); print (a,b); function2 (a, & b); print (a,b); void printint a[].int b){ for(int i-0;