Background:

A Date object contains a Number indicating a particular instant in time to within a millisecond. Such a Number is called a time value. A time value may also be NaN, indicating that the Date object does not represent a specific instant of time.

Time is measured in ECMAScript in milliseconds since 01 January, 1970 UTC. In time values leap seconds are ignored. It is assumed that there are exactly 86,400,000 milliseconds per day. ECMAScript Number values can represent all integers from -9,007,199,254,740,992 to 9,007,199,254,740,992; this range suffices to measure times to millisecond precision for any instant that is within approximately 285,616 years, either forward or backward, from 01 January, 1970 UTC.

The actual range of times supported by ECMAScript Date objects is slightly smaller: exactly -100,000,000 days to 100,000,000 days measured relative to midnight at the beginning of 01 January, 1970 UTC. This gives a range of 8,640,000,000,000,000 milliseconds to either side of 01 January, 1970 UTC.

The exact moment of midnight at the beginning of 01 January, 1970 UTC is represented by the value +0.

Assignment- Write the YearFromTime(t) function using if statements and while loops. The function requires entering a time (positive or negative in ms) and the output is the nearest year. It must take into account leap years. My program is not working and I'm not sure why. Can somebody tell me what I'm doing wrong? I have already written the following functions: TimeFromYear and DayFromYear.

YearFromTime(t) = the largest integer y (closest to positive infinity) such that TimeFromYear(y) t

(TimeFromYear(y) = msPerDay DayFromYear(y)

DayFromYear(y)=365 (y-1970) + floor((y-1969)/4) - floor((y-1901)/100) + floor((y-1601)/400))

int YearFromTime(long long int t) int yea r 1970; if(t >= 0) { while (TineFromYear(year) t) {