Balance the following interior angles $($angles$-$to$-$the$-$right$)$ of a five$-$sided closed polygon traverse. If the azimuth of side $AB$ is fixed at $218{59}^{\text{'}}{30}^{\text{'}\text{'}}$ calculate the azimuths of the remaining sides. $A=132{47}^{\text{'}\text{'}}{06}^{\text{'}\text{'}}$; $B=108{46}^{\text{'}}{18}^{\text{'}\text{'}}$;$C=107{19}^{\text{'}}{37}^{\text{'}\text{'}}$;$D=81{50}^{\text{'}}{36}^{\text{'}\text{'}}$;$E=109{16}^{\text{'}}{18}^{\text{'}\text{'}}.($Note: line $BC$ bears SE$.)$